\(\int \sec (c+d x) (a+b \sec (c+d x))^4 (A+C \sec ^2(c+d x)) \, dx\) [664]

Optimal result

Integrand size = 31, antiderivative size = 310 \[ \int \sec (c+d x) (a+b \sec (c+d x))^4 \left (A+C \sec ^2(c+d x)\right ) \, dx=\frac {\left (8 a^4 (2 A+C)+12 a^2 b^2 (4 A+3 C)+b^4 (6 A+5 C)\right ) \text {arctanh}(\sin (c+d x))}{16 d}-\frac {a \left (4 a^4 C-32 b^4 (5 A+4 C)-a^2 b^2 (190 A+121 C)\right ) \tan (c+d x)}{60 b d}-\frac {\left (8 a^4 C-15 b^4 (6 A+5 C)-2 a^2 b^2 (130 A+89 C)\right ) \sec (c+d x) \tan (c+d x)}{240 d}+\frac {a \left (70 A b^2-4 a^2 C+53 b^2 C\right ) (a+b \sec (c+d x))^2 \tan (c+d x)}{120 b d}-\frac {\left (4 a^2 C-5 b^2 (6 A+5 C)\right ) (a+b \sec (c+d x))^3 \tan (c+d x)}{120 b d}-\frac {a C (a+b \sec (c+d x))^4 \tan (c+d x)}{30 b d}+\frac {C (a+b \sec (c+d x))^5 \tan (c+d x)}{6 b d} \]

[Out]

1/16*(8*a^4*(2*A+C)+12*a^2*b^2*(4*A+3*C)+b^4*(6*A+5*C))*arctanh(sin(d*x+c))/d-1/60*a*(4*a^4*C-32*b^4*(5*A+4*C)
-a^2*b^2*(190*A+121*C))*tan(d*x+c)/b/d-1/240*(8*a^4*C-15*b^4*(6*A+5*C)-2*a^2*b^2*(130*A+89*C))*sec(d*x+c)*tan(
d*x+c)/d+1/120*a*(70*A*b^2-4*C*a^2+53*C*b^2)*(a+b*sec(d*x+c))^2*tan(d*x+c)/b/d-1/120*(4*C*a^2-5*b^2*(6*A+5*C))
*(a+b*sec(d*x+c))^3*tan(d*x+c)/b/d-1/30*a*C*(a+b*sec(d*x+c))^4*tan(d*x+c)/b/d+1/6*C*(a+b*sec(d*x+c))^5*tan(d*x
+c)/b/d

Rubi [A] (verified)

Time = 0.84 (sec) , antiderivative size = 310, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.226, Rules used = {4168, 4087, 4082, 3872, 3855, 3852, 8} \[ \int \sec (c+d x) (a+b \sec (c+d x))^4 \left (A+C \sec ^2(c+d x)\right ) \, dx=-\frac {\left (4 a^2 C-5 b^2 (6 A+5 C)\right ) \tan (c+d x) (a+b \sec (c+d x))^3}{120 b d}+\frac {a \left (-4 a^2 C+70 A b^2+53 b^2 C\right ) \tan (c+d x) (a+b \sec (c+d x))^2}{120 b d}+\frac {\left (8 a^4 (2 A+C)+12 a^2 b^2 (4 A+3 C)+b^4 (6 A+5 C)\right ) \text {arctanh}(\sin (c+d x))}{16 d}-\frac {a \left (4 a^4 C-a^2 b^2 (190 A+121 C)-32 b^4 (5 A+4 C)\right ) \tan (c+d x)}{60 b d}-\frac {\left (8 a^4 C-2 a^2 b^2 (130 A+89 C)-15 b^4 (6 A+5 C)\right ) \tan (c+d x) \sec (c+d x)}{240 d}+\frac {C \tan (c+d x) (a+b \sec (c+d x))^5}{6 b d}-\frac {a C \tan (c+d x) (a+b \sec (c+d x))^4}{30 b d} \]

[In]

Int[Sec[c + d*x]*(a + b*Sec[c + d*x])^4*(A + C*Sec[c + d*x]^2),x]

[Out]

((8*a^4*(2*A + C) + 12*a^2*b^2*(4*A + 3*C) + b^4*(6*A + 5*C))*ArcTanh[Sin[c + d*x]])/(16*d) - (a*(4*a^4*C - 32
*b^4*(5*A + 4*C) - a^2*b^2*(190*A + 121*C))*Tan[c + d*x])/(60*b*d) - ((8*a^4*C - 15*b^4*(6*A + 5*C) - 2*a^2*b^
2*(130*A + 89*C))*Sec[c + d*x]*Tan[c + d*x])/(240*d) + (a*(70*A*b^2 - 4*a^2*C + 53*b^2*C)*(a + b*Sec[c + d*x])
^2*Tan[c + d*x])/(120*b*d) - ((4*a^2*C - 5*b^2*(6*A + 5*C))*(a + b*Sec[c + d*x])^3*Tan[c + d*x])/(120*b*d) - (
a*C*(a + b*Sec[c + d*x])^4*Tan[c + d*x])/(30*b*d) + (C*(a + b*Sec[c + d*x])^5*Tan[c + d*x])/(6*b*d)

Rule 8

Int[a_, x_Symbol] :> Simp[a*x, x] /; FreeQ[a, x]

Rule 3852

Int[csc[(c_.) + (d_.)*(x_)]^(n_), x_Symbol] :> Dist[-d^(-1), Subst[Int[ExpandIntegrand[(1 + x^2)^(n/2 - 1), x]
, x], x, Cot[c + d*x]], x] /; FreeQ[{c, d}, x] && IGtQ[n/2, 0]

Rule 3855

Int[csc[(c_.) + (d_.)*(x_)], x_Symbol] :> Simp[-ArcTanh[Cos[c + d*x]]/d, x] /; FreeQ[{c, d}, x]

Rule 3872

Int[(csc[(e_.) + (f_.)*(x_)]*(d_.))^(n_.)*(csc[(e_.) + (f_.)*(x_)]*(b_.) + (a_)), x_Symbol] :> Dist[a, Int[(d*
Csc[e + f*x])^n, x], x] + Dist[b/d, Int[(d*Csc[e + f*x])^(n + 1), x], x] /; FreeQ[{a, b, d, e, f, n}, x]

Rule 4082

Int[(csc[(e_.) + (f_.)*(x_)]*(d_.))^(n_.)*(csc[(e_.) + (f_.)*(x_)]*(b_.) + (a_))*(csc[(e_.) + (f_.)*(x_)]*(B_.
) + (A_)), x_Symbol] :> Simp[(-b)*B*Cot[e + f*x]*((d*Csc[e + f*x])^n/(f*(n + 1))), x] + Dist[1/(n + 1), Int[(d
*Csc[e + f*x])^n*Simp[A*a*(n + 1) + B*b*n + (A*b + B*a)*(n + 1)*Csc[e + f*x], x], x], x] /; FreeQ[{a, b, d, e,
f, A, B}, x] && NeQ[A*b - a*B, 0] &&  !LeQ[n, -1]

Rule 4087

Int[csc[(e_.) + (f_.)*(x_)]*(csc[(e_.) + (f_.)*(x_)]*(b_.) + (a_))^(m_)*(csc[(e_.) + (f_.)*(x_)]*(B_.) + (A_))
, x_Symbol] :> Simp[(-B)*Cot[e + f*x]*((a + b*Csc[e + f*x])^m/(f*(m + 1))), x] + Dist[1/(m + 1), Int[Csc[e + f
*x]*(a + b*Csc[e + f*x])^(m - 1)*Simp[b*B*m + a*A*(m + 1) + (a*B*m + A*b*(m + 1))*Csc[e + f*x], x], x], x] /;
FreeQ[{a, b, A, B, e, f}, x] && NeQ[A*b - a*B, 0] && NeQ[a^2 - b^2, 0] && GtQ[m, 0]

Rule 4168

Int[csc[(e_.) + (f_.)*(x_)]*((A_.) + csc[(e_.) + (f_.)*(x_)]^2*(C_.))*(csc[(e_.) + (f_.)*(x_)]*(b_.) + (a_))^(
m_), x_Symbol] :> Simp[(-C)*Cot[e + f*x]*((a + b*Csc[e + f*x])^(m + 1)/(b*f*(m + 2))), x] + Dist[1/(b*(m + 2))
, Int[Csc[e + f*x]*(a + b*Csc[e + f*x])^m*Simp[b*A*(m + 2) + b*C*(m + 1) - a*C*Csc[e + f*x], x], x], x] /; Fre
eQ[{a, b, e, f, A, C, m}, x] &&  !LtQ[m, -1]

Rubi steps \begin{align*} \text {integral}& = \frac {C (a+b \sec (c+d x))^5 \tan (c+d x)}{6 b d}+\frac {\int \sec (c+d x) (a+b \sec (c+d x))^4 (b (6 A+5 C)-a C \sec (c+d x)) \, dx}{6 b} \\ & = -\frac {a C (a+b \sec (c+d x))^4 \tan (c+d x)}{30 b d}+\frac {C (a+b \sec (c+d x))^5 \tan (c+d x)}{6 b d}+\frac {\int \sec (c+d x) (a+b \sec (c+d x))^3 \left (3 a b (10 A+7 C)-\left (4 a^2 C-5 b^2 (6 A+5 C)\right ) \sec (c+d x)\right ) \, dx}{30 b} \\ & = -\frac {\left (4 a^2 C-5 b^2 (6 A+5 C)\right ) (a+b \sec (c+d x))^3 \tan (c+d x)}{120 b d}-\frac {a C (a+b \sec (c+d x))^4 \tan (c+d x)}{30 b d}+\frac {C (a+b \sec (c+d x))^5 \tan (c+d x)}{6 b d}+\frac {\int \sec (c+d x) (a+b \sec (c+d x))^2 \left (3 b \left (8 a^2 (5 A+3 C)+5 b^2 (6 A+5 C)\right )+3 a \left (70 A b^2-4 a^2 C+53 b^2 C\right ) \sec (c+d x)\right ) \, dx}{120 b} \\ & = \frac {a \left (70 A b^2-4 a^2 C+53 b^2 C\right ) (a+b \sec (c+d x))^2 \tan (c+d x)}{120 b d}-\frac {\left (4 a^2 C-5 b^2 (6 A+5 C)\right ) (a+b \sec (c+d x))^3 \tan (c+d x)}{120 b d}-\frac {a C (a+b \sec (c+d x))^4 \tan (c+d x)}{30 b d}+\frac {C (a+b \sec (c+d x))^5 \tan (c+d x)}{6 b d}+\frac {\int \sec (c+d x) (a+b \sec (c+d x)) \left (3 a b \left (8 a^2 (15 A+8 C)+b^2 (230 A+181 C)\right )-3 \left (8 a^4 C-15 b^4 (6 A+5 C)-2 a^2 b^2 (130 A+89 C)\right ) \sec (c+d x)\right ) \, dx}{360 b} \\ & = -\frac {\left (8 a^4 C-15 b^4 (6 A+5 C)-2 a^2 b^2 (130 A+89 C)\right ) \sec (c+d x) \tan (c+d x)}{240 d}+\frac {a \left (70 A b^2-4 a^2 C+53 b^2 C\right ) (a+b \sec (c+d x))^2 \tan (c+d x)}{120 b d}-\frac {\left (4 a^2 C-5 b^2 (6 A+5 C)\right ) (a+b \sec (c+d x))^3 \tan (c+d x)}{120 b d}-\frac {a C (a+b \sec (c+d x))^4 \tan (c+d x)}{30 b d}+\frac {C (a+b \sec (c+d x))^5 \tan (c+d x)}{6 b d}+\frac {\int \sec (c+d x) \left (45 b \left (8 a^4 (2 A+C)+12 a^2 b^2 (4 A+3 C)+b^4 (6 A+5 C)\right )-12 a \left (4 a^4 C-32 b^4 (5 A+4 C)-a^2 b^2 (190 A+121 C)\right ) \sec (c+d x)\right ) \, dx}{720 b} \\ & = -\frac {\left (8 a^4 C-15 b^4 (6 A+5 C)-2 a^2 b^2 (130 A+89 C)\right ) \sec (c+d x) \tan (c+d x)}{240 d}+\frac {a \left (70 A b^2-4 a^2 C+53 b^2 C\right ) (a+b \sec (c+d x))^2 \tan (c+d x)}{120 b d}-\frac {\left (4 a^2 C-5 b^2 (6 A+5 C)\right ) (a+b \sec (c+d x))^3 \tan (c+d x)}{120 b d}-\frac {a C (a+b \sec (c+d x))^4 \tan (c+d x)}{30 b d}+\frac {C (a+b \sec (c+d x))^5 \tan (c+d x)}{6 b d}+\frac {1}{16} \left (8 a^4 (2 A+C)+12 a^2 b^2 (4 A+3 C)+b^4 (6 A+5 C)\right ) \int \sec (c+d x) \, dx-\frac {\left (a \left (4 a^4 C-32 b^4 (5 A+4 C)-a^2 b^2 (190 A+121 C)\right )\right ) \int \sec ^2(c+d x) \, dx}{60 b} \\ & = \frac {\left (8 a^4 (2 A+C)+12 a^2 b^2 (4 A+3 C)+b^4 (6 A+5 C)\right ) \text {arctanh}(\sin (c+d x))}{16 d}-\frac {\left (8 a^4 C-15 b^4 (6 A+5 C)-2 a^2 b^2 (130 A+89 C)\right ) \sec (c+d x) \tan (c+d x)}{240 d}+\frac {a \left (70 A b^2-4 a^2 C+53 b^2 C\right ) (a+b \sec (c+d x))^2 \tan (c+d x)}{120 b d}-\frac {\left (4 a^2 C-5 b^2 (6 A+5 C)\right ) (a+b \sec (c+d x))^3 \tan (c+d x)}{120 b d}-\frac {a C (a+b \sec (c+d x))^4 \tan (c+d x)}{30 b d}+\frac {C (a+b \sec (c+d x))^5 \tan (c+d x)}{6 b d}+\frac {\left (a \left (4 a^4 C-32 b^4 (5 A+4 C)-a^2 b^2 (190 A+121 C)\right )\right ) \text {Subst}(\int 1 \, dx,x,-\tan (c+d x))}{60 b d} \\ & = \frac {\left (8 a^4 (2 A+C)+12 a^2 b^2 (4 A+3 C)+b^4 (6 A+5 C)\right ) \text {arctanh}(\sin (c+d x))}{16 d}-\frac {a \left (4 a^4 C-32 b^4 (5 A+4 C)-a^2 b^2 (190 A+121 C)\right ) \tan (c+d x)}{60 b d}-\frac {\left (8 a^4 C-15 b^4 (6 A+5 C)-2 a^2 b^2 (130 A+89 C)\right ) \sec (c+d x) \tan (c+d x)}{240 d}+\frac {a \left (70 A b^2-4 a^2 C+53 b^2 C\right ) (a+b \sec (c+d x))^2 \tan (c+d x)}{120 b d}-\frac {\left (4 a^2 C-5 b^2 (6 A+5 C)\right ) (a+b \sec (c+d x))^3 \tan (c+d x)}{120 b d}-\frac {a C (a+b \sec (c+d x))^4 \tan (c+d x)}{30 b d}+\frac {C (a+b \sec (c+d x))^5 \tan (c+d x)}{6 b d} \\ \end{align*}

Mathematica [A] (verified)

Time = 8.88 (sec) , antiderivative size = 207, normalized size of antiderivative = 0.67 \[ \int \sec (c+d x) (a+b \sec (c+d x))^4 \left (A+C \sec ^2(c+d x)\right ) \, dx=\frac {15 \left (8 a^4 (2 A+C)+12 a^2 b^2 (4 A+3 C)+b^4 (6 A+5 C)\right ) \text {arctanh}(\sin (c+d x))+\tan (c+d x) \left (15 \left (8 a^4 C+12 a^2 b^2 (4 A+3 C)+b^4 (6 A+5 C)\right ) \sec (c+d x)+10 b^2 \left (6 A b^2+36 a^2 C+5 b^2 C\right ) \sec ^3(c+d x)+40 b^4 C \sec ^5(c+d x)+64 a b \left (15 \left (a^2+b^2\right ) (A+C)+5 \left (A b^2+a^2 C+2 b^2 C\right ) \tan ^2(c+d x)+3 b^2 C \tan ^4(c+d x)\right )\right )}{240 d} \]

[In]

Integrate[Sec[c + d*x]*(a + b*Sec[c + d*x])^4*(A + C*Sec[c + d*x]^2),x]

[Out]

(15*(8*a^4*(2*A + C) + 12*a^2*b^2*(4*A + 3*C) + b^4*(6*A + 5*C))*ArcTanh[Sin[c + d*x]] + Tan[c + d*x]*(15*(8*a
^4*C + 12*a^2*b^2*(4*A + 3*C) + b^4*(6*A + 5*C))*Sec[c + d*x] + 10*b^2*(6*A*b^2 + 36*a^2*C + 5*b^2*C)*Sec[c +
d*x]^3 + 40*b^4*C*Sec[c + d*x]^5 + 64*a*b*(15*(a^2 + b^2)*(A + C) + 5*(A*b^2 + a^2*C + 2*b^2*C)*Tan[c + d*x]^2
+ 3*b^2*C*Tan[c + d*x]^4)))/(240*d)

Maple [A] (verified)

Time = 1.57 (sec) , antiderivative size = 291, normalized size of antiderivative = 0.94

method	result	size
parts	\(\frac {\left (A \,b^{4}+6 C \,a^{2} b^{2}\right ) \left (-\left (-\frac {\sec \left (d x +c \right )^{3}}{4}-\frac {3 \sec \left (d x +c \right )}{8}\right ) \tan \left (d x +c \right )+\frac {3 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{8}\right )}{d}-\frac {\left (4 a A \,b^{3}+4 a^{3} b C \right ) \left (-\frac {2}{3}-\frac {\sec \left (d x +c \right )^{2}}{3}\right ) \tan \left (d x +c \right )}{d}+\frac {\left (6 A \,a^{2} b^{2}+a^{4} C \right ) \left (\frac {\sec \left (d x +c \right ) \tan \left (d x +c \right )}{2}+\frac {\ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{2}\right )}{d}+\frac {C \,b^{4} \left (-\left (-\frac {\sec \left (d x +c \right )^{5}}{6}-\frac {5 \sec \left (d x +c \right )^{3}}{24}-\frac {5 \sec \left (d x +c \right )}{16}\right ) \tan \left (d x +c \right )+\frac {5 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{16}\right )}{d}+\frac {A \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right ) a^{4}}{d}+\frac {4 A \,a^{3} b \tan \left (d x +c \right )}{d}-\frac {4 C a \,b^{3} \left (-\frac {8}{15}-\frac {\sec \left (d x +c \right )^{4}}{5}-\frac {4 \sec \left (d x +c \right )^{2}}{15}\right ) \tan \left (d x +c \right )}{d}\)	\(291\)
derivativedivides	\(\frac {a^{4} A \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )+a^{4} C \left (\frac {\sec \left (d x +c \right ) \tan \left (d x +c \right )}{2}+\frac {\ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{2}\right )+4 A \,a^{3} b \tan \left (d x +c \right )-4 a^{3} b C \left (-\frac {2}{3}-\frac {\sec \left (d x +c \right )^{2}}{3}\right ) \tan \left (d x +c \right )+6 A \,a^{2} b^{2} \left (\frac {\sec \left (d x +c \right ) \tan \left (d x +c \right )}{2}+\frac {\ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{2}\right )+6 C \,a^{2} b^{2} \left (-\left (-\frac {\sec \left (d x +c \right )^{3}}{4}-\frac {3 \sec \left (d x +c \right )}{8}\right ) \tan \left (d x +c \right )+\frac {3 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{8}\right )-4 a A \,b^{3} \left (-\frac {2}{3}-\frac {\sec \left (d x +c \right )^{2}}{3}\right ) \tan \left (d x +c \right )-4 C a \,b^{3} \left (-\frac {8}{15}-\frac {\sec \left (d x +c \right )^{4}}{5}-\frac {4 \sec \left (d x +c \right )^{2}}{15}\right ) \tan \left (d x +c \right )+A \,b^{4} \left (-\left (-\frac {\sec \left (d x +c \right )^{3}}{4}-\frac {3 \sec \left (d x +c \right )}{8}\right ) \tan \left (d x +c \right )+\frac {3 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{8}\right )+C \,b^{4} \left (-\left (-\frac {\sec \left (d x +c \right )^{5}}{6}-\frac {5 \sec \left (d x +c \right )^{3}}{24}-\frac {5 \sec \left (d x +c \right )}{16}\right ) \tan \left (d x +c \right )+\frac {5 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{16}\right )}{d}\)	\(360\)
default	\(\frac {a^{4} A \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )+a^{4} C \left (\frac {\sec \left (d x +c \right ) \tan \left (d x +c \right )}{2}+\frac {\ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{2}\right )+4 A \,a^{3} b \tan \left (d x +c \right )-4 a^{3} b C \left (-\frac {2}{3}-\frac {\sec \left (d x +c \right )^{2}}{3}\right ) \tan \left (d x +c \right )+6 A \,a^{2} b^{2} \left (\frac {\sec \left (d x +c \right ) \tan \left (d x +c \right )}{2}+\frac {\ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{2}\right )+6 C \,a^{2} b^{2} \left (-\left (-\frac {\sec \left (d x +c \right )^{3}}{4}-\frac {3 \sec \left (d x +c \right )}{8}\right ) \tan \left (d x +c \right )+\frac {3 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{8}\right )-4 a A \,b^{3} \left (-\frac {2}{3}-\frac {\sec \left (d x +c \right )^{2}}{3}\right ) \tan \left (d x +c \right )-4 C a \,b^{3} \left (-\frac {8}{15}-\frac {\sec \left (d x +c \right )^{4}}{5}-\frac {4 \sec \left (d x +c \right )^{2}}{15}\right ) \tan \left (d x +c \right )+A \,b^{4} \left (-\left (-\frac {\sec \left (d x +c \right )^{3}}{4}-\frac {3 \sec \left (d x +c \right )}{8}\right ) \tan \left (d x +c \right )+\frac {3 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{8}\right )+C \,b^{4} \left (-\left (-\frac {\sec \left (d x +c \right )^{5}}{6}-\frac {5 \sec \left (d x +c \right )^{3}}{24}-\frac {5 \sec \left (d x +c \right )}{16}\right ) \tan \left (d x +c \right )+\frac {5 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{16}\right )}{d}\)	\(360\)
parallelrisch	\(\frac {-240 \left (\cos \left (6 d x +6 c \right )+6 \cos \left (4 d x +4 c \right )+15 \cos \left (2 d x +2 c \right )+10\right ) \left (\left (\frac {3 A}{8}+\frac {5 C}{16}\right ) b^{4}+3 \left (A +\frac {3 C}{4}\right ) a^{2} b^{2}+a^{4} \left (A +\frac {C}{2}\right )\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )+240 \left (\cos \left (6 d x +6 c \right )+6 \cos \left (4 d x +4 c \right )+15 \cos \left (2 d x +2 c \right )+10\right ) \left (\left (\frac {3 A}{8}+\frac {5 C}{16}\right ) b^{4}+3 \left (A +\frac {3 C}{4}\right ) a^{2} b^{2}+a^{4} \left (A +\frac {C}{2}\right )\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )+\left (\left (1020 A +850 C \right ) b^{4}+4320 a^{2} \left (A +\frac {17 C}{12}\right ) b^{2}+720 a^{4} C \right ) \sin \left (3 d x +3 c \right )+\left (\left (180 A +150 C \right ) b^{4}+1440 \left (A +\frac {3 C}{4}\right ) a^{2} b^{2}+240 a^{4} C \right ) \sin \left (5 d x +5 c \right )+4800 a b \left (\left (\frac {6 A}{5}+\frac {8 C}{5}\right ) b^{2}+a^{2} \left (A +\frac {6 C}{5}\right )\right ) \sin \left (2 d x +2 c \right )+3840 a b \left (b^{2} \left (A +\frac {4 C}{5}\right )+\left (A +C \right ) a^{2}\right ) \sin \left (4 d x +4 c \right )+960 a b \left (\left (\frac {2 A}{3}+\frac {8 C}{15}\right ) b^{2}+a^{2} \left (A +\frac {2 C}{3}\right )\right ) \sin \left (6 d x +6 c \right )+2880 \left (\left (\frac {7 A}{24}+\frac {11 C}{16}\right ) b^{4}+a^{2} \left (A +\frac {7 C}{4}\right ) b^{2}+\frac {a^{4} C}{6}\right ) \sin \left (d x +c \right )}{240 d \left (\cos \left (6 d x +6 c \right )+6 \cos \left (4 d x +4 c \right )+15 \cos \left (2 d x +2 c \right )+10\right )}\)	\(422\)
norman	\(\frac {-\frac {\left (64 A \,a^{3} b -48 A \,a^{2} b^{2}+64 a A \,b^{3}-10 A \,b^{4}-8 a^{4} C +64 a^{3} b C -60 C \,a^{2} b^{2}+64 C a \,b^{3}-11 C \,b^{4}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{11}}{8 d}+\frac {\left (64 A \,a^{3} b +48 A \,a^{2} b^{2}+64 a A \,b^{3}+10 A \,b^{4}+8 a^{4} C +64 a^{3} b C +60 C \,a^{2} b^{2}+64 C a \,b^{3}+11 C \,b^{4}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{8 d}+\frac {\left (960 A \,a^{3} b -432 A \,a^{2} b^{2}+704 a A \,b^{3}-42 A \,b^{4}-72 a^{4} C +704 a^{3} b C -252 C \,a^{2} b^{2}+448 C a \,b^{3}+5 C \,b^{4}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{9}}{24 d}-\frac {\left (960 A \,a^{3} b +432 A \,a^{2} b^{2}+704 a A \,b^{3}+42 A \,b^{4}+72 a^{4} C +704 a^{3} b C +252 C \,a^{2} b^{2}+448 C a \,b^{3}-5 C \,b^{4}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{3}}{24 d}-\frac {\left (1600 A \,a^{3} b -240 A \,a^{2} b^{2}+960 a A \,b^{3}-10 A \,b^{4}-40 a^{4} C +960 a^{3} b C -60 C \,a^{2} b^{2}+832 C a \,b^{3}-75 C \,b^{4}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{7}}{20 d}+\frac {\left (1600 A \,a^{3} b +240 A \,a^{2} b^{2}+960 a A \,b^{3}+10 A \,b^{4}+40 a^{4} C +960 a^{3} b C +60 C \,a^{2} b^{2}+832 C a \,b^{3}+75 C \,b^{4}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{5}}{20 d}}{\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}-1\right )^{6}}-\frac {\left (16 a^{4} A +48 A \,a^{2} b^{2}+6 A \,b^{4}+8 a^{4} C +36 C \,a^{2} b^{2}+5 C \,b^{4}\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )}{16 d}+\frac {\left (16 a^{4} A +48 A \,a^{2} b^{2}+6 A \,b^{4}+8 a^{4} C +36 C \,a^{2} b^{2}+5 C \,b^{4}\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )}{16 d}\)	\(623\)
risch	\(\text {Expression too large to display}\)	\(1067\)

[In]

int(sec(d*x+c)*(a+b*sec(d*x+c))^4*(A+C*sec(d*x+c)^2),x,method=_RETURNVERBOSE)

[Out]

(A*b^4+6*C*a^2*b^2)/d*(-(-1/4*sec(d*x+c)^3-3/8*sec(d*x+c))*tan(d*x+c)+3/8*ln(sec(d*x+c)+tan(d*x+c)))-(4*A*a*b^
3+4*C*a^3*b)/d*(-2/3-1/3*sec(d*x+c)^2)*tan(d*x+c)+(6*A*a^2*b^2+C*a^4)/d*(1/2*sec(d*x+c)*tan(d*x+c)+1/2*ln(sec(
d*x+c)+tan(d*x+c)))+C*b^4/d*(-(-1/6*sec(d*x+c)^5-5/24*sec(d*x+c)^3-5/16*sec(d*x+c))*tan(d*x+c)+5/16*ln(sec(d*x
+c)+tan(d*x+c)))+1/d*A*ln(sec(d*x+c)+tan(d*x+c))*a^4+4*A*a^3*b/d*tan(d*x+c)-4*C*a*b^3/d*(-8/15-1/5*sec(d*x+c)^
4-4/15*sec(d*x+c)^2)*tan(d*x+c)

Fricas [A] (verification not implemented)

none

Time = 0.28 (sec) , antiderivative size = 297, normalized size of antiderivative = 0.96 \[ \int \sec (c+d x) (a+b \sec (c+d x))^4 \left (A+C \sec ^2(c+d x)\right ) \, dx=\frac {15 \, {\left (8 \, {\left (2 \, A + C\right )} a^{4} + 12 \, {\left (4 \, A + 3 \, C\right )} a^{2} b^{2} + {\left (6 \, A + 5 \, C\right )} b^{4}\right )} \cos \left (d x + c\right )^{6} \log \left (\sin \left (d x + c\right ) + 1\right ) - 15 \, {\left (8 \, {\left (2 \, A + C\right )} a^{4} + 12 \, {\left (4 \, A + 3 \, C\right )} a^{2} b^{2} + {\left (6 \, A + 5 \, C\right )} b^{4}\right )} \cos \left (d x + c\right )^{6} \log \left (-\sin \left (d x + c\right ) + 1\right ) + 2 \, {\left (192 \, C a b^{3} \cos \left (d x + c\right ) + 64 \, {\left (5 \, {\left (3 \, A + 2 \, C\right )} a^{3} b + 2 \, {\left (5 \, A + 4 \, C\right )} a b^{3}\right )} \cos \left (d x + c\right )^{5} + 40 \, C b^{4} + 15 \, {\left (8 \, C a^{4} + 12 \, {\left (4 \, A + 3 \, C\right )} a^{2} b^{2} + {\left (6 \, A + 5 \, C\right )} b^{4}\right )} \cos \left (d x + c\right )^{4} + 64 \, {\left (5 \, C a^{3} b + {\left (5 \, A + 4 \, C\right )} a b^{3}\right )} \cos \left (d x + c\right )^{3} + 10 \, {\left (36 \, C a^{2} b^{2} + {\left (6 \, A + 5 \, C\right )} b^{4}\right )} \cos \left (d x + c\right )^{2}\right )} \sin \left (d x + c\right )}{480 \, d \cos \left (d x + c\right )^{6}} \]

[In]

integrate(sec(d*x+c)*(a+b*sec(d*x+c))^4*(A+C*sec(d*x+c)^2),x, algorithm="fricas")

[Out]

1/480*(15*(8*(2*A + C)*a^4 + 12*(4*A + 3*C)*a^2*b^2 + (6*A + 5*C)*b^4)*cos(d*x + c)^6*log(sin(d*x + c) + 1) -
15*(8*(2*A + C)*a^4 + 12*(4*A + 3*C)*a^2*b^2 + (6*A + 5*C)*b^4)*cos(d*x + c)^6*log(-sin(d*x + c) + 1) + 2*(192
*C*a*b^3*cos(d*x + c) + 64*(5*(3*A + 2*C)*a^3*b + 2*(5*A + 4*C)*a*b^3)*cos(d*x + c)^5 + 40*C*b^4 + 15*(8*C*a^4
+ 12*(4*A + 3*C)*a^2*b^2 + (6*A + 5*C)*b^4)*cos(d*x + c)^4 + 64*(5*C*a^3*b + (5*A + 4*C)*a*b^3)*cos(d*x + c)^
3 + 10*(36*C*a^2*b^2 + (6*A + 5*C)*b^4)*cos(d*x + c)^2)*sin(d*x + c))/(d*cos(d*x + c)^6)

Sympy [F]

\[ \int \sec (c+d x) (a+b \sec (c+d x))^4 \left (A+C \sec ^2(c+d x)\right ) \, dx=\int \left (A + C \sec ^{2}{\left (c + d x \right )}\right ) \left (a + b \sec {\left (c + d x \right )}\right )^{4} \sec {\left (c + d x \right )}\, dx \]

[In]

integrate(sec(d*x+c)*(a+b*sec(d*x+c))**4*(A+C*sec(d*x+c)**2),x)

[Out]

Integral((A + C*sec(c + d*x)**2)*(a + b*sec(c + d*x))**4*sec(c + d*x), x)

Maxima [A] (verification not implemented)

none

Time = 0.20 (sec) , antiderivative size = 459, normalized size of antiderivative = 1.48 \[ \int \sec (c+d x) (a+b \sec (c+d x))^4 \left (A+C \sec ^2(c+d x)\right ) \, dx=\frac {640 \, {\left (\tan \left (d x + c\right )^{3} + 3 \, \tan \left (d x + c\right )\right )} C a^{3} b + 640 \, {\left (\tan \left (d x + c\right )^{3} + 3 \, \tan \left (d x + c\right )\right )} A a b^{3} + 128 \, {\left (3 \, \tan \left (d x + c\right )^{5} + 10 \, \tan \left (d x + c\right )^{3} + 15 \, \tan \left (d x + c\right )\right )} C a b^{3} - 5 \, C b^{4} {\left (\frac {2 \, {\left (15 \, \sin \left (d x + c\right )^{5} - 40 \, \sin \left (d x + c\right )^{3} + 33 \, \sin \left (d x + c\right )\right )}}{\sin \left (d x + c\right )^{6} - 3 \, \sin \left (d x + c\right )^{4} + 3 \, \sin \left (d x + c\right )^{2} - 1} - 15 \, \log \left (\sin \left (d x + c\right ) + 1\right ) + 15 \, \log \left (\sin \left (d x + c\right ) - 1\right )\right )} - 180 \, C a^{2} b^{2} {\left (\frac {2 \, {\left (3 \, \sin \left (d x + c\right )^{3} - 5 \, \sin \left (d x + c\right )\right )}}{\sin \left (d x + c\right )^{4} - 2 \, \sin \left (d x + c\right )^{2} + 1} - 3 \, \log \left (\sin \left (d x + c\right ) + 1\right ) + 3 \, \log \left (\sin \left (d x + c\right ) - 1\right )\right )} - 30 \, A b^{4} {\left (\frac {2 \, {\left (3 \, \sin \left (d x + c\right )^{3} - 5 \, \sin \left (d x + c\right )\right )}}{\sin \left (d x + c\right )^{4} - 2 \, \sin \left (d x + c\right )^{2} + 1} - 3 \, \log \left (\sin \left (d x + c\right ) + 1\right ) + 3 \, \log \left (\sin \left (d x + c\right ) - 1\right )\right )} - 120 \, C a^{4} {\left (\frac {2 \, \sin \left (d x + c\right )}{\sin \left (d x + c\right )^{2} - 1} - \log \left (\sin \left (d x + c\right ) + 1\right ) + \log \left (\sin \left (d x + c\right ) - 1\right )\right )} - 720 \, A a^{2} b^{2} {\left (\frac {2 \, \sin \left (d x + c\right )}{\sin \left (d x + c\right )^{2} - 1} - \log \left (\sin \left (d x + c\right ) + 1\right ) + \log \left (\sin \left (d x + c\right ) - 1\right )\right )} + 480 \, A a^{4} \log \left (\sec \left (d x + c\right ) + \tan \left (d x + c\right )\right ) + 1920 \, A a^{3} b \tan \left (d x + c\right )}{480 \, d} \]

[In]

integrate(sec(d*x+c)*(a+b*sec(d*x+c))^4*(A+C*sec(d*x+c)^2),x, algorithm="maxima")

[Out]

1/480*(640*(tan(d*x + c)^3 + 3*tan(d*x + c))*C*a^3*b + 640*(tan(d*x + c)^3 + 3*tan(d*x + c))*A*a*b^3 + 128*(3*
tan(d*x + c)^5 + 10*tan(d*x + c)^3 + 15*tan(d*x + c))*C*a*b^3 - 5*C*b^4*(2*(15*sin(d*x + c)^5 - 40*sin(d*x + c
)^3 + 33*sin(d*x + c))/(sin(d*x + c)^6 - 3*sin(d*x + c)^4 + 3*sin(d*x + c)^2 - 1) - 15*log(sin(d*x + c) + 1) +
15*log(sin(d*x + c) - 1)) - 180*C*a^2*b^2*(2*(3*sin(d*x + c)^3 - 5*sin(d*x + c))/(sin(d*x + c)^4 - 2*sin(d*x
+ c)^2 + 1) - 3*log(sin(d*x + c) + 1) + 3*log(sin(d*x + c) - 1)) - 30*A*b^4*(2*(3*sin(d*x + c)^3 - 5*sin(d*x +
c))/(sin(d*x + c)^4 - 2*sin(d*x + c)^2 + 1) - 3*log(sin(d*x + c) + 1) + 3*log(sin(d*x + c) - 1)) - 120*C*a^4*
(2*sin(d*x + c)/(sin(d*x + c)^2 - 1) - log(sin(d*x + c) + 1) + log(sin(d*x + c) - 1)) - 720*A*a^2*b^2*(2*sin(d
*x + c)/(sin(d*x + c)^2 - 1) - log(sin(d*x + c) + 1) + log(sin(d*x + c) - 1)) + 480*A*a^4*log(sec(d*x + c) + t
an(d*x + c)) + 1920*A*a^3*b*tan(d*x + c))/d

Giac [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 1100 vs. \(2 (296) = 592\).

Time = 0.41 (sec) , antiderivative size = 1100, normalized size of antiderivative = 3.55 \[ \int \sec (c+d x) (a+b \sec (c+d x))^4 \left (A+C \sec ^2(c+d x)\right ) \, dx=\text {Too large to display} \]

[In]

integrate(sec(d*x+c)*(a+b*sec(d*x+c))^4*(A+C*sec(d*x+c)^2),x, algorithm="giac")

[Out]

1/240*(15*(16*A*a^4 + 8*C*a^4 + 48*A*a^2*b^2 + 36*C*a^2*b^2 + 6*A*b^4 + 5*C*b^4)*log(abs(tan(1/2*d*x + 1/2*c)
+ 1)) - 15*(16*A*a^4 + 8*C*a^4 + 48*A*a^2*b^2 + 36*C*a^2*b^2 + 6*A*b^4 + 5*C*b^4)*log(abs(tan(1/2*d*x + 1/2*c)
- 1)) + 2*(120*C*a^4*tan(1/2*d*x + 1/2*c)^11 - 960*A*a^3*b*tan(1/2*d*x + 1/2*c)^11 - 960*C*a^3*b*tan(1/2*d*x
+ 1/2*c)^11 + 720*A*a^2*b^2*tan(1/2*d*x + 1/2*c)^11 + 900*C*a^2*b^2*tan(1/2*d*x + 1/2*c)^11 - 960*A*a*b^3*tan(
1/2*d*x + 1/2*c)^11 - 960*C*a*b^3*tan(1/2*d*x + 1/2*c)^11 + 150*A*b^4*tan(1/2*d*x + 1/2*c)^11 + 165*C*b^4*tan(
1/2*d*x + 1/2*c)^11 - 360*C*a^4*tan(1/2*d*x + 1/2*c)^9 + 4800*A*a^3*b*tan(1/2*d*x + 1/2*c)^9 + 3520*C*a^3*b*ta
n(1/2*d*x + 1/2*c)^9 - 2160*A*a^2*b^2*tan(1/2*d*x + 1/2*c)^9 - 1260*C*a^2*b^2*tan(1/2*d*x + 1/2*c)^9 + 3520*A*
a*b^3*tan(1/2*d*x + 1/2*c)^9 + 2240*C*a*b^3*tan(1/2*d*x + 1/2*c)^9 - 210*A*b^4*tan(1/2*d*x + 1/2*c)^9 + 25*C*b
^4*tan(1/2*d*x + 1/2*c)^9 + 240*C*a^4*tan(1/2*d*x + 1/2*c)^7 - 9600*A*a^3*b*tan(1/2*d*x + 1/2*c)^7 - 5760*C*a^
3*b*tan(1/2*d*x + 1/2*c)^7 + 1440*A*a^2*b^2*tan(1/2*d*x + 1/2*c)^7 + 360*C*a^2*b^2*tan(1/2*d*x + 1/2*c)^7 - 57
60*A*a*b^3*tan(1/2*d*x + 1/2*c)^7 - 4992*C*a*b^3*tan(1/2*d*x + 1/2*c)^7 + 60*A*b^4*tan(1/2*d*x + 1/2*c)^7 + 45
0*C*b^4*tan(1/2*d*x + 1/2*c)^7 + 240*C*a^4*tan(1/2*d*x + 1/2*c)^5 + 9600*A*a^3*b*tan(1/2*d*x + 1/2*c)^5 + 5760
*C*a^3*b*tan(1/2*d*x + 1/2*c)^5 + 1440*A*a^2*b^2*tan(1/2*d*x + 1/2*c)^5 + 360*C*a^2*b^2*tan(1/2*d*x + 1/2*c)^5
+ 5760*A*a*b^3*tan(1/2*d*x + 1/2*c)^5 + 4992*C*a*b^3*tan(1/2*d*x + 1/2*c)^5 + 60*A*b^4*tan(1/2*d*x + 1/2*c)^5
+ 450*C*b^4*tan(1/2*d*x + 1/2*c)^5 - 360*C*a^4*tan(1/2*d*x + 1/2*c)^3 - 4800*A*a^3*b*tan(1/2*d*x + 1/2*c)^3 -
3520*C*a^3*b*tan(1/2*d*x + 1/2*c)^3 - 2160*A*a^2*b^2*tan(1/2*d*x + 1/2*c)^3 - 1260*C*a^2*b^2*tan(1/2*d*x + 1/
2*c)^3 - 3520*A*a*b^3*tan(1/2*d*x + 1/2*c)^3 - 2240*C*a*b^3*tan(1/2*d*x + 1/2*c)^3 - 210*A*b^4*tan(1/2*d*x + 1
/2*c)^3 + 25*C*b^4*tan(1/2*d*x + 1/2*c)^3 + 120*C*a^4*tan(1/2*d*x + 1/2*c) + 960*A*a^3*b*tan(1/2*d*x + 1/2*c)
+ 960*C*a^3*b*tan(1/2*d*x + 1/2*c) + 720*A*a^2*b^2*tan(1/2*d*x + 1/2*c) + 900*C*a^2*b^2*tan(1/2*d*x + 1/2*c) +
960*A*a*b^3*tan(1/2*d*x + 1/2*c) + 960*C*a*b^3*tan(1/2*d*x + 1/2*c) + 150*A*b^4*tan(1/2*d*x + 1/2*c) + 165*C*
b^4*tan(1/2*d*x + 1/2*c))/(tan(1/2*d*x + 1/2*c)^2 - 1)^6)/d

Mupad [B] (verification not implemented)

Time = 19.12 (sec) , antiderivative size = 690, normalized size of antiderivative = 2.23 \[ \int \sec (c+d x) (a+b \sec (c+d x))^4 \left (A+C \sec ^2(c+d x)\right ) \, dx=\frac {\left (\frac {5\,A\,b^4}{4}+C\,a^4+\frac {11\,C\,b^4}{8}+6\,A\,a^2\,b^2+\frac {15\,C\,a^2\,b^2}{2}-8\,A\,a\,b^3-8\,A\,a^3\,b-8\,C\,a\,b^3-8\,C\,a^3\,b\right )\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{11}+\left (\frac {5\,C\,b^4}{24}-3\,C\,a^4-\frac {7\,A\,b^4}{4}-18\,A\,a^2\,b^2-\frac {21\,C\,a^2\,b^2}{2}+\frac {88\,A\,a\,b^3}{3}+40\,A\,a^3\,b+\frac {56\,C\,a\,b^3}{3}+\frac {88\,C\,a^3\,b}{3}\right )\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^9+\left (\frac {A\,b^4}{2}+2\,C\,a^4+\frac {15\,C\,b^4}{4}+12\,A\,a^2\,b^2+3\,C\,a^2\,b^2-48\,A\,a\,b^3-80\,A\,a^3\,b-\frac {208\,C\,a\,b^3}{5}-48\,C\,a^3\,b\right )\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^7+\left (\frac {A\,b^4}{2}+2\,C\,a^4+\frac {15\,C\,b^4}{4}+12\,A\,a^2\,b^2+3\,C\,a^2\,b^2+48\,A\,a\,b^3+80\,A\,a^3\,b+\frac {208\,C\,a\,b^3}{5}+48\,C\,a^3\,b\right )\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5+\left (\frac {5\,C\,b^4}{24}-3\,C\,a^4-\frac {7\,A\,b^4}{4}-18\,A\,a^2\,b^2-\frac {21\,C\,a^2\,b^2}{2}-\frac {88\,A\,a\,b^3}{3}-40\,A\,a^3\,b-\frac {56\,C\,a\,b^3}{3}-\frac {88\,C\,a^3\,b}{3}\right )\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3+\left (\frac {5\,A\,b^4}{4}+C\,a^4+\frac {11\,C\,b^4}{8}+6\,A\,a^2\,b^2+\frac {15\,C\,a^2\,b^2}{2}+8\,A\,a\,b^3+8\,A\,a^3\,b+8\,C\,a\,b^3+8\,C\,a^3\,b\right )\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}{d\,\left ({\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{12}-6\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{10}+15\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^8-20\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6+15\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4-6\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+1\right )}+\frac {\mathrm {atanh}\left (\frac {4\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\,\left (A\,a^4+\frac {3\,A\,b^4}{8}+\frac {C\,a^4}{2}+\frac {5\,C\,b^4}{16}+3\,A\,a^2\,b^2+\frac {9\,C\,a^2\,b^2}{4}\right )}{4\,A\,a^4+\frac {3\,A\,b^4}{2}+2\,C\,a^4+\frac {5\,C\,b^4}{4}+12\,A\,a^2\,b^2+9\,C\,a^2\,b^2}\right )\,\left (2\,A\,a^4+\frac {3\,A\,b^4}{4}+C\,a^4+\frac {5\,C\,b^4}{8}+6\,A\,a^2\,b^2+\frac {9\,C\,a^2\,b^2}{2}\right )}{d} \]

[In]

int(((A + C/cos(c + d*x)^2)*(a + b/cos(c + d*x))^4)/cos(c + d*x),x)

[Out]

(tan(c/2 + (d*x)/2)*((5*A*b^4)/4 + C*a^4 + (11*C*b^4)/8 + 6*A*a^2*b^2 + (15*C*a^2*b^2)/2 + 8*A*a*b^3 + 8*A*a^3
*b + 8*C*a*b^3 + 8*C*a^3*b) + tan(c/2 + (d*x)/2)^11*((5*A*b^4)/4 + C*a^4 + (11*C*b^4)/8 + 6*A*a^2*b^2 + (15*C*
a^2*b^2)/2 - 8*A*a*b^3 - 8*A*a^3*b - 8*C*a*b^3 - 8*C*a^3*b) - tan(c/2 + (d*x)/2)^3*((7*A*b^4)/4 + 3*C*a^4 - (5
*C*b^4)/24 + 18*A*a^2*b^2 + (21*C*a^2*b^2)/2 + (88*A*a*b^3)/3 + 40*A*a^3*b + (56*C*a*b^3)/3 + (88*C*a^3*b)/3)
+ tan(c/2 + (d*x)/2)^9*((5*C*b^4)/24 - 3*C*a^4 - (7*A*b^4)/4 - 18*A*a^2*b^2 - (21*C*a^2*b^2)/2 + (88*A*a*b^3)/
3 + 40*A*a^3*b + (56*C*a*b^3)/3 + (88*C*a^3*b)/3) + tan(c/2 + (d*x)/2)^5*((A*b^4)/2 + 2*C*a^4 + (15*C*b^4)/4 +
12*A*a^2*b^2 + 3*C*a^2*b^2 + 48*A*a*b^3 + 80*A*a^3*b + (208*C*a*b^3)/5 + 48*C*a^3*b) + tan(c/2 + (d*x)/2)^7*(
(A*b^4)/2 + 2*C*a^4 + (15*C*b^4)/4 + 12*A*a^2*b^2 + 3*C*a^2*b^2 - 48*A*a*b^3 - 80*A*a^3*b - (208*C*a*b^3)/5 -
48*C*a^3*b))/(d*(15*tan(c/2 + (d*x)/2)^4 - 6*tan(c/2 + (d*x)/2)^2 - 20*tan(c/2 + (d*x)/2)^6 + 15*tan(c/2 + (d*
x)/2)^8 - 6*tan(c/2 + (d*x)/2)^10 + tan(c/2 + (d*x)/2)^12 + 1)) + (atanh((4*tan(c/2 + (d*x)/2)*(A*a^4 + (3*A*b
^4)/8 + (C*a^4)/2 + (5*C*b^4)/16 + 3*A*a^2*b^2 + (9*C*a^2*b^2)/4))/(4*A*a^4 + (3*A*b^4)/2 + 2*C*a^4 + (5*C*b^4
)/4 + 12*A*a^2*b^2 + 9*C*a^2*b^2))*(2*A*a^4 + (3*A*b^4)/4 + C*a^4 + (5*C*b^4)/8 + 6*A*a^2*b^2 + (9*C*a^2*b^2)/
2))/d